Wednesday, October 3, 2007

Monday, October 1, 2007

Waves in Two Dimensions Review

Today in class we went over questions 16 and 17 in the green booklet on Waves in two dimensions. We also corrected the answers on the review sheets so we can prepare for the test on Wednesday.
Scribe for Thursday is kristina

Sunday, September 30, 2007

Wednesday Sept 26 (i know im kinda late sorry)

On Wednesday we had a substitute and his name was Mr. Whiteway (he was a English teacher so he wasn't much help). We received 2 handouts on Refraction. One was about how light refracted and the other was exercises on Refraction.

Friday September 29

Hi, I'm Thi and I'll be scribing for Friday's Class. On Friday, we watched a video disk on interference of two circular waves and Diffraction. Note: I put diffraction in bold and Italics because it may be on a test. Diffraction occurs when a wave, for example, made in a ripple tank hits an obstacle. Although the wave may reflect, it will also pass through the barrier at its ends. This causes the wave to slightly bend and is known as diffraction. Diffraction can change a straight wave into almost a circular wave.

When two identical waves that are produced by two point sources collide, they interference with one another. This results in crests overlapping crests, troughs on troughs and even crests on troughs. Areas of destructive interference and constructive interference are created. As shown in the Waves in Two Dimensions booklet and the assignment we received, dotted lines are correspondent with the troughs, solid lines with crests and the grey area is the path of the nodal lines.

Page 17 of the booklet displays what this looks like and explains everything I just said and more.Click to see Page 17

After that we received a worksheet on interference and that is basically all I can remember of Friday's Class.


Since I am the last one to scribe, I guess I have the honour of choosing the next scribe. The next scribe shall be Kevin! For future references, I stink at blogging and this is goodbye for now.

Friday, September 28, 2007

Monday, September 24, 2007

Hey this is Eric, and I'm today's scribe.

Today in class we watched a video of a crazy teacher who explained waves in two dimensions: reflection and refraction. We also got a worksheet to fill out while we watched the video.

After that, we looked over the answers, which everyone should have since we did them in class.

We then went over the answers for last week's homework, which was:
Questions 5 to 8 in the green booklet


Answers:


Finally, we got an assignment on Refraction that doesn't have to be done for tomorrow, but it would be good if you did some. Also, don't forget to do your research projects!

That's all for today, and the next scribe is Melissa since the scribe today was actually supposed to be her

Saturday, September 22, 2007

Hello. This is lauressa.

Well today in class we went over page 12 in our green booklet; waves in two dimensions, and learned about Snell's Law. Snell's Law shows that the ratio of the sine of the angle of incidence and the sine of the angle of refraction is a constant. The constant we use in Snell's Law is referred to as the index of refraction. With Snell's Law it can be used to determine a number of things, for instance the speeds and the wavelengths of incident or refracted waves by this equation

For those who aren't quite sure what refraction is it occurs when waves approach a boundary between two water depths at an angle causing the direction of travel of the refracted waves change. Since the value of n are ratio it doesn't have any specific unit of measurement, but the value of n, is specific for certain materials like air, glass, and water. For Snell's Law we also used old equations but with a little twist. As we all know velocity V, can be found by multiplying frequency F x wavelength λ. Well we can use that equation for help with Snell's Law by putting deep .vs. shallow in front the the characters to solve for the velocity of the deep and shallow water.

After we learned about Snell's law Ms.K handed out an assignment to test how much we could put our knowledge to use. Here was the example questions and the answers if you didn't manage to get them in class.

A water wave of frequency 10.0Hz and speed 40cm/s is traveling in deep water. It then moves into shallow water where its speed is 30cm/s. The angle of refraction is 30°

Find
A) The index of refraction
n=Vdeep /V shallow

n=(40cm/s)/(30cm/s)

n=1.33

B) The wavelengths in the two media

Deep
λdeep=Vdeep/F


=(40cm/s)/10.0Hz

λdeep=4cm

Shallow
λshallow=Vshallow/F

=(30cm/s)/10.0Hz

λshallow=3cm

C)the angle of refraction in the shallow water.
For this question there is more than one way to solve it .


~solution 1~
n=
sinθi/sinθr

sinθr=sin30°/1.33

sinθr=0.375 or 22°


~solution 2~
sinθ
i/sinθr=Vi/Vr

sinθr=(sinθi x Vr)/Vi

=(sin30° x 30cm/s)/(40cm/s)

sinθr=0.375 or 22°


~solution 3~
sin
θi/sinθr=λdeep/λshallow

sinθr=(sinθi x λshallow)/λdeep

=(sin30
° x 3 cm)/4cm

sinθr=0.375 or 22°

Well that was pretty much it for our class on Friday, but for those who haven't already, the assignment for the week were questions 5-8 in our green booklet, and our wave research project is due on Tuesday. See you all on Monday!!
O yea the next scribe is Melissa

If you're thinking you should realize that question #6 is a repeat of the question we did on the whiteboard.